## Wiring multiple leds techdose.com electricity wikipedia in hindi

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What happens if you want to light 20 LEDs in the same circuit? There must be a way to do this without needing a 60v power supply as would be required if you wired the LEDs in series. Well, the answer my friend — is parallel wiring. When wiring LEDs in parallel you’re creating seperate mini circuits, each with their own 6v power supply. Each circuit consists of the battery (positive, ground), an LED and a resistor.

In the schematic below there are 3 LEDs, each are part of a different mini circuit. If you removed one of the LEDs from the circuit, the other LEDs would still light brightly just as they had before. You’re only limited by the current the battery is capable of supplying. So you could theoretically hook up 20 or 30 LEDs to the same 6v battery, but you would find the battery dies quicker depending on the number of LEDs you’re hooking up and total amps being used by all the components in the circuit.

Below is a picture of my 3 LEDs wired in parallel (as in the schematic above) on a breadboard. It’s the exact same circuit as in the Solderless Breadboard tutorial, only with two more mini circuits! Just connect the other two sets of LEDs the same way to the postive / ground rails and you’re set!

Now try hooking up multiple LEDs in series and parallel! Remembere to use V/I = R to figure out what (if any) resistor values you will need to bring the LED operating voltage within spec. There are a lot more mathematical equations involved here to figure out how long the battery can supply the power, whether you’re exceeding the amps of the supply, etc.. but when using a lower voltage battery supply you’re pretty safe. I wonder how many LEDs can be hooked up to a single battery? Sounds like a good topic for a future tutorial!

Wiring LEDs in series is pretty easy — and a great way to learn how wiring in series affects the voltage and current on the circuit. In college, they taught us with actual light bulbs with sockets that we’d clip together in series with various leads — ah, the good old days!

When wiring up any electrical circuit, the equation V=IR (otherwise known as Ohms Law) is imporant in figuring out the voltage and resistance at various points and the limits of the circuit. An interesting thing with series circuits is while the voltage drop will change based on the number of components you’re hooking up, the current remains the same across the entire circuit.

Why no resistors? When wiring in series, the current remains the same across the circuit, but the voltage still changes based on the number of components being hooked up. So since both LEDs need around 3v to light up, they’re essentially using all of the 6v of the power supply in that circuit up and balancing some complex equations. If you had a 9v power supply, you could wire up 3 LEDs in series.. however with just a 6v power supply if you tried adding a 3rd LED the voltage drop of 9v would exceed the power supplies voltage enough that the LEDs wouldn’t be getting the ~3v voltage they need to operate. This is probably why we used light bulbs in college, cause you would see the bulbs starting to dim as you hooked more and more bulbs in series, whereas an LED is more finicky about voltage requirements.

Below is a picture of two LEDs wired in series on my breadboard with a 6v battery supply as in the schematic. Notice that that (from left to right) the positive rail of the power supply connects to a jumper. The jumper connects to the anode of the first LED. The cathode of the first LED is then in the same row as the anode of the second LED. And the cathode of the second LED is in a totally different row that is then connected to the ground rail to complete the circuit.